C语言实现绘制南丁格尔玫瑰图的示例代码
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Canvas cs ;
float pi=3.1415926535 ;
float a ;
float r ;
int i, j, n ;
float x0,y0,x1,y1 ;
float dx,dy ;
string ss, ss1, ss2 ;
int p[6] ;
double pn ;
RoseChart10 (){
cs.ClearDraw (0,src);
clearOutput();
selectStyle () ;
cs.SetFillMode (1);
cs.SetColor (255,250,250,250);
cs.DrawRect (0,4,720,600);
cs.SetColor (255,140,140,140);
cs.DrawRect (24,24,706,586);
cs.SetColor (255,240,240,250);
cs.DrawRect (20,20,700,580);
cs.SetFillMode (0);
cs.SetColor (255,0,0,240);
cs.DrawRect (20,20,700,580);
cs.DrawRect (24,24,696,576);
cs.SetStrokeWidth(0);
dx=360; dy=280 ;
cs.SetFillMode (1);
cs.SetColor(255,80,20,250);
cs.DrawCircle(dx,dy,215);
int cr,cg,cb;
for (i=1; i<=11 ; i++){
cb=200-i*25 ;
L=cb+40 ;
cs.SetColor(255,80,0,cb);
cs.DrawCircle(dx,dy,L); }
cs.SetColor(255,80,0,40);
cs.DrawCircle(dx,dy,15);
cs.SetTextStyle (1);
cs.SetStrokeWidth(1);
cs.SetColor(255,250,0,0);
cs.SetTextSize (16);
for (i=1; i<=10 ; i++){
a=pi/360*i ;
x0=(float)(200*cos (a))+dx ;
y0=(float)(200*sin (a))+dy ;
cs.SetFillMode (0);
cs.SetColor(255,250,250,250);
cs.DrawCircle(dx,dy,i*20);
x1=(float)(i*20*cos (a))+dx ;
y1=(float)(i*20*sin (a))+dy ;
ss=intToString (i);
cs.SetFillMode (1);
cs.SetColor(255,250,250,0);
cs.DrawText(ss,x1-5,285); }
cs.SetTextSize (18);
cs.SetColor(255,250,0,0);
for (i=0; i<=5 ; i++){
a=pi/360*i*120 ;
x0=(float)(220*cos(a))+dx ;
y0=(float)(-220*sin(a))+dy ;
cs.DrawLine (x0,y0,dx,dy);
a=pi/360*i*120+120 ;
x1=(float)(225*cos(a))+dx-5 ;
y1=(float)(-225*sin(a))+dy+5 ;
ss=intToString (i+1) ;
cs.DrawText (ss,x1,y1) ; }
cs.SetColor (255,220,200,250);
cs.DrawRect (550,80,685,180);
cs.SetColor (255,250,0,0);
cs.DrawRect (630,90,670,110);
cs.DrawText ("Group A", 560,105) ;
cs.SetColor (255,0,250,0);
cs.DrawRect (630,120,670,140);
cs.DrawText ("Group B", 560,135) ;
cs.SetColor (255,250,250,0);
cs.DrawRect (630,150,670,170);
cs.DrawText ("Group C", 560,165) ;
int p1[6], p2[6], p3[6] ;
int L ;
cs.SetStrokeWidth(2);
cs.SetFillMode (1);
p1[0]=70; p1[1]=85; p1[2]=68; p1[3]=94;
p1[4]=60; p1[5]=75;
for (n=0; n<=5 ; n++){
r=p1[n]+120 ;
for (i= n*120+20; i<=n*120+100; i++){
cs.SetColor(200,250,0,0);
a=pi/360*i ;
x0=(float)(r*cos (a))+dx ;
y0=(float)(-r*sin (a))+dy ;
cs.DrawLine (dx,dy,x0,y0);
cs.DrawRect (80,n*25+52,120,n*25+74);
cs.SetTextStyle (0);
cs.SetTextSize (18);
cs.SetColor(255,0,0,250);
s=intToString(n+1)+" > "+intToString (p1[n]);
cs.DrawText (s, 55,70+n*25);
cs.Update (); } }
p2[0]=78; p2[1]=65; p2[2]=69; p2[3]=70;
p2[4]=80; p2[5]=95;
for (n=0; n<=5 ; n++){
r=p2[n]+80 ;
for (i= n*120+20; i<=n*120+100; i++){
cs.SetColor(200,0,250,0);
a=pi/360*i ;
x0=(float)(r*cos (a))+dx ;
y0=(float)(-r*sin (a))+dy ;
cs.DrawLine (dx,dy,x0,y0);
cs.DrawRect (80,n*25+213,120,n*25+234);
cs.SetTextStyle (0);
cs.SetTextSize (18);
cs.SetColor(255,0,0,250);
s=intToString(n+1)+" > "+intToString (p2[n]);
cs.DrawText (s, 55,230+n*25);
cs.Update (); } }
p3[0]=50; p3[1]=75; p3[2]=88; p3[3]=85;
p3[4]=97; p3[5]=70;
for (n=0; n<=5 ; n++){
r=p3[n]+40 ;
for (i= n*120+20; i<=n*120+100; i++){
cs.SetColor(150,250,250,0);
a=pi/360*i ;
x0=(float)(r*cos (a))+dx ;
y0=(float)(-r*sin (a))+dy ;
cs.DrawLine (dx,dy,x0,y0);
cs.DrawRect (80,n*25+373,120,n*25+394);
cs.SetTextStyle (0);
cs.SetTextSize (18);
cs.SetColor(255,0,0,250);
s=intToString(n+1)+" > "+intToString (p3[n]);
cs.DrawText (s, 55,390+n*25);
cs.Update (); } }
cs.SetFillMode (0);
cs.SetStrokeWidth(2);
cs.SetColor(255,250,0,0);
cs.DrawCircle(dx,dy,215);
cs.SetColor(255,0,250,0);
cs.DrawCircle(dx,dy,180);
cs.SetColor(255,250,250,0);
cs.DrawCircle(dx,dy,140);
cs.SetFillMode (1);
cs.SetTextStyle (1);
cs.SetStrokeWidth(1);
cs.SetTextSize (26);
cs.SetColor(255,0,0,250);
cs.DrawText ("Rose Chart ",500,60) ;
cs.SetTextSize (50);
ss="统计图 － 玫瑰图" ;
cs.SetColor(255,50,120,20);
cs.DrawText (ss,164,534);
cs.SetColor(255,0,250,0);
cs.DrawText (ss,160,530);
cs.SetFillMode (0);
cs.SetColor(255,250,150,0);
cs.DrawText (ss,160,530);
cs.Update ();
}
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